NECO Chemistry Practical Questions and Answers2021/2022( Complete result)
NECO Chemistry Practical 2021. numerous NECO campaigners find it delicate to answer the NECO Practical Chemistry Alternative A and B rightly due to not understanding the questions. I'll show you the stylish way to answer the 2021 NECO Chemistry Practical questions and make a good grade in your Chemistry examination.
It's material you understand the NECO Chemistry Practical timber scheme before trying any questions so as to present your answers in such a way that it'll look seductive to the monitor to earn you big ma
Bearit in mind that every single procedure is awarded marks. So, insure you don't skip any step while reporting and presenting your practical results.
The Chemistry Practical question paper will correspond of two sections and general Chemistry questions videlicet
Quantitative Analysis
Qualitative Analysis
These involve titration and test of ions. You'll be anticipated to carry out an trial and report your conclusion and observation. What you'll see won't be far from the NECO Chemistry Specimen given to your academy.
Note Your titration endpoint will be given to you by your Chemistry schoolteacher. It isn't the same for every academy but within a range.
Don't use the endpoint then. It may vary from your center endpoint but you can follow the computation procedures.
1.NECO Chemistry Specimen 2022
2 NECO Practical Chemistry Questions and Answers( exhibit)
NECO Chemistry Specimen 2020
NECO Chemistry Specimen 2021
TITRATION
i) Adulterate sodium hydroxide result
ii) Adulterate ammonia result
iii) Adulterate hydrochloric acid
iv) Adulterate trioxonitrate( V) acid
v) Distilled water
vi) Red and blue litmus test paper
vii) Barium chloride result
viii) Phenolphthalein result
ix) Methyl orange
x) One boiling tube
xi) Five test tubes
xii) Source of heat
xiii) Wash bottle containing distilled water
xiv) Filtration apparatu
NECO Practical Chemistry Questions and Answers( exhibit)
Note The 2021 NECO Chemistry Practical answers will be posted then moment Wednesday, 14th July during the NECO Practical Chemistry test. Keep checking and reloading this runner to know when the answers are posted. Don't forget to reload this runner in order to see the answers.
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moment’s Chemistry Practical Answers
1a)
Tabulate
Volume of pipette used = 25cm3.
Indicator used = Methyl orange
Under Titration, Rough, 1st, 2nd, 3rd,
Final burette reading;|25.00||23.40||23.50|23.60|
original burette reading;|0.00||0.00||0.00||0.00|
Volume of A used;|25.00||23.40||23.50||23.60|
1ai)
Average volume of Acid used = 23.4023.5023.60/ 3 = 70.5/ 3 = 23.50 cm3
1aii)
This is because it's a response between a weak acid and strong base
1aiii)
A channel should be used while transferring the acid into the burette.
1bi)
Conc of A in spook| dm ³ = ?
Conc of A in g| dm ³ = 12.75 g| dm ³
Molar mass of A, NaHSO ⁴ = 23 1 32 64
= 120g| dm ³
From.
Conc( spook/ dm ³) = conc( g/ dm ³) molar mass
Conc = 12.75/ 120
Conc = 0.106 spook/ dm ³
1bii)
Con of B in spook/ dm ³ = ?
Ca = 0.106, Cb = ? Va = 23.50 cm ³, Vb = 25.00 cm ³
na = 1, nb = 1
From; CaVa/ CbVb = na/ nb
Cb = CaVanb/ Vbna
Cb = 0.10623501/25.001
Cb = 2.5/ 25
Cb = 0.1 spook/ dm ³
1biii)
Conc of B in g/ dm ³ = ?
Molar mass of B, NaOH = 23 16 1 = 40g/ spook
From; conc( g/ dm ³) = conc( spook/ dm ³) molar mass
= 0.140
= 4.0 g/ dm ³
1biv)
Mass of swab formed = ?
Recall operative of NaHSO ⁴ = ?
From; operative = con( spook/ dm ³) * vol( cm ³) 1000
operative = 0.106 *23.50/ 1000
operative = 0.0025 spook of NaHSO ⁴
By proportion 1mol of NaHSO ⁴ yield 1mol of Na ² SO ⁴0.0025 spook of NaHSO ⁴ will produce X spook of Na ² SO ⁴ X = 0.00251 = 0.0025 spook of NaSO ⁴
Molar mass of Na ² SO ⁴ = ( 232) 32( 16 * 4)
= 46 32 64
= 142g/ spook
Recall; operative = operative/ molar mass
Mass = operative * molar mass
Mass = 0.0025 * 142
Mass = 0.36 g of Na ² SO ⁴
( 2a)
PLEASE PUT IN A TABULAR FORM)
TEST
C 5 cm ³ of distilled water
OBSERVATION
It dissolve fully
hindrance
C is a answerable swab
2bi)
TEST
result NaOH Heat
OBSERVATION
Effervescence occurs in which a colourless gas with pungent smell and turns red litmus test paper to blue is given off.
consequences
NH ³ gas from NH ⁴ is present
2bii)
TEST
Stirring rod of HCL gas given off
OBSERVATION
a gas which gives a pop sound is given off
consequences
H ² is present
2ci)
TEST
result C drops of BaCL ²
OBSERVATION
a white precipitate is formed
consequences
CO ²- 3, SO ²- 4, SO ²- 3, May be present.
2cii)
TEST
result in C( i) dil HCL
OBSERVATION
the white precipitate dissolve is dil HCL and effervescence occurs in which a colourless and odourless gas which turns blue litmus test red and lime water milky is given off
hindrance
CO ² gas from CO ² 3- verified
===================================================
3a)
i) Ca ²
ii) Pb ²
3bi)
concentrated acid can be defined as an acid formed when a large volume of an acid dissolve in a small or little volume of water.
3bii)
A strong acid is defined as a type of acid that ionize fully in a result
3c)
Actuated watercolor is used as an adsorbent material
3d)
i) Sanguine – Brown
ii) I – red, II – brown.
—
NECO Chemistry Specimen 2020
CHEMISTRY PRACTICAL instance
Conditions
a) One burette( 50 cm ³)
b) One pippete( 20 cm ³/ 25 cm ³). still, all
campaigners in a center must use pipettes of the
same volume.
c) The usual outfit and reagents for
qualitative work including
i) Adulterate sodium hydroxide result
ii) Adulterate ammonia result
iii) Adulterate hydrochloric acid
iv) Barium chloride result
v) Distilled water
vi) Red and Blue litmus test paper
vii) Phenolphtalein
d) Methyl orange
e) One boiling tube
f) Five test tubes
g) Filtration outfit
h) Source of heat
Each seeker should be supplied with the
following Labelled An, Bn, Cn, where ‘ n ’ is the
seeker’s periodical number.
a) 150 cm ³ of chloride acid result in a bottle
labelled “ An ”. The acid result which should
be the same for all campaigners will contain
cm ³ of the concentrated hydrochloric acid
per dm ³ result.
b) 150 cm ³ of sodium hydroxide result in a
bottle labelled “ Bn ”. The result which should
be the same for all campaigners will contain
g of sodium hydroxide per dm ³ of result.
c) One spatulaful of bobby
( ii)
tetraoxosulphate( vi) swab in a instance bottle
labelled “ Cn ”.
The questions below are rigorously for practice not the 2021 Chemistry exhibit.
All your burette readings( initials and final) as well as the size of your pipette must be recorded but no account of experimented procedure is needed. All computations must be done in your folder.
A isO. 200 moldm3 of HCI. C is a result containing 14/ 3g of Na2CO3. x H2O in 500 cm3 of result.( a) Put A into the burette and titrate it against20.0 cm3 or25.0 cm3 portions of C using methyl orange as index. Repeat the titration to gain harmonious titre values. Tabulate your results and calculate the average volume of A used. The equation for the response is Na2CO3 x H2O 2HCL( aq) → 2NaCI( aq) CO2( g)( x 1) H2O( I).
b) From your results and the information handed. Calculate the( i) attention of C in moldm- 3;( ii) attention of C in gdm- 3;( iii) molar mass of Na2CO3, xH2O;( iv) the value of x in Na2CO3 xH2O.( H = 1.0; C = 12.0; O = 16.0; Na = 23.0)
Credit will be given for strict adherence to the instruction, for compliances precisely recorded and for accurate consequences. All tests, compliances and influences must be easily entered in the folder in essay at the same time they're made.
2. F is a admixture to two inorganic mariners. Carry out the following exercise onF. record your observation and identify any gas( s) evolved. State the conclusions you draw from the result of each test.( a) Put all of F in a teacup and add about 10cm3 of distilled water. Stir well and sludge. Keep the filtrate and the residue.( b)( i) To about 2cm3 of the filtrate, add NaOH( aq) in drops and also in redundant( ii) To another 2cm3 portion of the result, add a many drops of NHO3( aq) followed by many drops of AgNO3( aq).( d)( i) Put all the residue into a clean test- tube and add NHO3( aq) followed by many result from 2( d)( i) add NaOH( aq) in drops and also in excess.
3. State what would be observed if the following responses are carried out in the laboratory( i) methyl orange is dropped into a result of lime juice( ii) hydrogen sulphide gas is gurgled through iron( III) chloride result;( iii) sulphur( IV) oxide gas is gurgled into acidified result of KMnO4;( iv) ethanoic acid is added to a result of K2CO3.
CHEMISTRY PRACTICALS ANSWERS
Indicator = Methyl Orange
Volume of the base used = 25.00 cm3
Titration Rough Titre 1st Titre 2nd Titre 3rd Titre
Final Burette readings cm324.7024.8024.7024.90
original Burette reading cm30.000.000.000.00
Volume of acid used cm324.7024.8024.9024.90
Average Titre = 1st 2nd 3rd/ 3
= 24.8024.7024.90/ 3
= 24.80 cm3
Alternately 2 accordant titres can be used to calculate average titre.
Equation of the response Na2CO3 XH2O 2HCI( aq) → 2NacI( aq) CO2( aq)( x 1) H2O( I)
CAVA/ CBVB = nA/ nB
CA = Molar attention of HCI( aq) in moldm3
VA = Volume of acid used in cm3 = 24.80 cm3
CB = Molar attention of Na2Cu3 xH2O in moldm3
nA = 2
nB = 1
b)( i) attention of C in moldm- 3 = ? From the equation of response
CAVA/ CBVB = nA/ nB
CA = 0.200 moldm3 VA = 24.80 cm3
CB = ? VB = 25.00 cm3
Negotiation of known values
x24.80/ CB x25.00 = 2/1
CB = 1 ×0.200 ×24.80/ 2 ×25.00
CB = 0.0992 moldm- 3
ii) attention of C in g dm- 3 = ?
500cm2 →14.3 g
1000cm3 →14.3/ 500 x 10002 g
= 28.6 g dm- 3
iii) Molar mass of Na2CO3 xH2O
Molar conc in moldm- 3 = conc in g dm- 3/ molar mass
thus Molar mass g spook- 1 = conc in g dm- 3/ molar conc in moldm- 3
= 28.6 g dm-3/0.0992 moldm- 3
= 288.3065
roughly 288 g spook- 1
iv) Value of x in Na2CO3 xH2O?
H = 1.0, C = 12.0, O = 16.0, Na = 23.0)
Na2CO3 xH2O = 288
2( 23) 12 3( 16) x( 2( I) 16) = 288
46 12 48 18x = 288
106 18x = 288
18x = 288
18x = 182
x = 182/18
x = 10.11
x roughly 10
2 Test Observation Inference
a) F distil water stir sludge Effervescence( washing) occurs, colourless and odourless gas evolved after filtration blench blue/ colourless filtrate and green residue
( b)( i) Filtrate NaOH( aq) in drops also in redundant White precipitate formed Precipitate undoable in redundant NaOH( aq) Ca2/ Pb2 Ca2 present
b)( ii) Filtrate NH3( aq) in drops also in redundant No visible response No visible response OR Ca2 present Ca2 verified
b)( i) Filtrate NaOH( aq) in drops also in redundant Blue glutinous precipitate formed Precipitate undoable in redundant Cu2 is present
b)( ii) Filtrate NH3( aq) in drops also in redundant Pale( light) blue glutinous precipitate formed Precipitate dissolves to form a deep blue result Cu2 Cu2 is verified
c) Filtrate NHO3( aq) AgNO3( aq) No visible response No gas involved White precipitate formed CuI is present
d)( i) Residue HNO3( aq) Efferveness occurs, colourless and odourless gas evolves that turn blue litmus test paper to red and turns lime water milky CO2( g) CO32-present
( d)( ii) result from 2( d)( i) NaOH( aq) in drops also in redundant Blue precipitate formed Precipitate undoable in redundant NaOH( aq) Cu2 Cu2 present
( ii) result from 2( d)( i) NaOH( aq) in drops also in redundant Blue precipitate formed Precipitate undoable in redundant NaOH( aq) Cu2 Cu2 present
3( a)( i) result of lime juice turns to pink or red.( ii) The FeCI3 result changes colour from brown to green and a unheroic deposit.( iii) The grandiloquent colour of the KMnO4 result turns colourless or decolourised.( iv) The result of K2CO3 reacts with the addition of ethanoic acid to evolve a colourless, odourless gas with washing of effervescence.
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