(1)
S|N; 1|2|3|4|5|
M(g); 40.0|60.0|80.0|100.0|120.0|
X(cm);37.50|25.01|8.75|15.00|12.50|
X-¹(cm-¹); 0.027| 0.040|0.|053|0.067|0.08|
X-¹(x10-³); 27.00|40.00|53.00|67.00|80.00|
G=50.0cm
Y=30.0cm
Slope =∆M/∆X^-1= M2-M1/(X^-1) - (X^-1)
S= 120.0 -40/80.0-27
S= 80/53
S=1.509*10^3
S=1509
(x)
S=ymo
1509=30mo
mo=1509/30
mo=50.3
(1xi)
(i)Measure readings accurately
(ii)Avoid error due to parallax
(1bii)
CWM = ACWM
60*25 = x *30
30x = 1500
Divide through by 30
30x/30 = 1500/30
x=50g
The mass that should be placed at the 80cm mark of the meter rule to balance it horizontally is 50g
(1bi)
Moment of a force can be defined as the product of the force and its perpendicular distance from its point of action.
(1a)
Typing......
(1bi) Moment of a force can be defined as the product of the force and its perpendicular distance from its point of action.
(1bii)
Typing......
(3a)
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(3bi)
(1) connecting cells in parallel adds the current capacities together.
(2) connecting cells in parallel provides alternative Pathways for Current flows.
(3) When cells are connected in parallel the Total voltage provided do not change
(3bii)
(i) Resistance.
(ii) Tolerance.
(iii) Rated Power Dissipation.
(iv) Package and mounting.
(iv) Voltage rating.
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